2. a scooter moves at a speed of 36km/h is stopped by applying brakes which produce a uniform acceleration of, -0.5m/s . how much distance will be covered by the scooter before it stops?

There will be covered 100 meter by the scooter before it stops.

Explanation:

Step 1: Data given

Velocity of the scooter = 36 km/h = 10 m/s = the initial velocity

Uniform acceleration = -0.5 m/s

Step 2:  Calculate time needed to stop the scooter

Suppose the scooter stops afer time t, then v= 0

v = v0+ a*t = 0    a = -0.5 m/s²

0 = 10 + (-0.5)*t

-10 = -0.5t

t= 20

This means the scooter will stop after 20 seconds

Step 3: Calculate distance travelled before the scooter stops

x = v0*t + 1/2at²

x = 10*20 + 1/2*(-0.5)*20²

x = 200 -100

x = 100 m

There will be covered 100 meter by the scooter before it stops.

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