(25%) problem 3: a bullet is fired horizontally into an initially stationary block of wood suspended by a string and remains embedded in the block. the bullet’s mass is m = 0.0085 kg, while that of the block is m = 0.99 kg. after the collision the block/bullet system swings and reaches a maximum height of h = 0.95 m above its initial height. neglect air resistance.

The initial velocity of the bullet is 507.4 m/s

Your question is not complete, it seems to be missing the following information;

find the initial velocity of the bullet

The given parameters;

The final velocity of the system is calculated as;

The initial velocity of the bullet is calculated by applying the principle of conservation of linear momentum;

Thus, the initial velocity of the bullet is 507.4 m/s

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explanation:

we need to know the time interval during which the force acts. impulse of force = momentum change