A2.40 kg stone is sliding in the +x-direction on a horizontal, frictionless surface. it collides with a 4.00 kg stone at rest. after the collision the 2.40 kg stone is moving at 3.60 m/s at an angle of 30.0∘ measured from the +x-direction toward the +y-direction and the 4.00 kg stone is moving at an angle of 45.0∘ measured from the +x-direction toward the −y-direction. what is the y-component of momentum of the 2.40 kg stone after the collision?

4.32 kg.m/s

Explanation:

SInce the 2.4 kg stone is mobing at speed of 3.6m/s at an angle of 30 degree measured from the x+ direction toward y+ direction. Its y-component momentum is product of its velocity in the y-direction and its mass

i need the answer to this too but idk it ; -;

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.