Aperson wants to use a lever to lift a dumpster weighing 4200 n.4200 n. the lever is arranged so that it is approximately horizontal and makes contact below the dumpster's center of mass at a distance of 0.30 m0.30 m from the lever's pivot. about how much torque will the dumpster exert on the lever?

1260 Nm

Explanation:

As one end of the lever makes contact at the point right below the dumpster center of mass and has a distance of 0.3 m to the lever pivot point, plus the fact that the level is also approximately horizontal, we can safely assume that the dumpster gravity is directly perpendicular to the level.

This would make the torque caused by the dumpster gravity on the level is

T = LF = 4200*0.3 = 1260 Nm

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~