A1,198 n sky diver has opened his parachute to slow his descent to a constant speed the parachute applies 1,277 n of force. he experiences a 7.5 m/s2 deceleration. what is the mass of the sky diver?

The mass of the skydiver is 10.53 kg.

Explanation:

Force of the sky diver acting downwards due to gravity  =   1198 N

Force of the parachute acting upwards against gravity  =   1,277 N

Net Up word Force  = F Upwards - F downwards

                                 =1,277 N  -  1198 N  = 79 N

Deceleration  on the parachute  = 7.5m/s2

⇒ Acceleration  = - 7.5 m / s2

Now, FORCE = MASS x ACCELERATION

or, 79 N  =  M x (7.5 m /s2)

⇒ M  = 79/7.5  = 10 . 53 kg

or, mass  = 10.53 kg

Hence, the mass of the skydiver is 10.53 kg.

i would like to make dinner for my mom, dad, and sister

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s