What is the maximum speed with which a 1500 kg car can make a left turn around a curve of radius 50 m on a level road without sliding

v = 22.14 m/s

Explanation:

Given,

The mass of the car, m = 1500 Kg

The radius of the curved level road, r = 50 m

The normal force acting on the car,

                               F = m x g

                                  = 1500 x 9.8

                                   = 14700 N

Neglecting the frictional force, this is the force exerted by the car tires on the road.

In sharp curves, the centrifugal force acts on the car.

This force should not be greater than the normal force of the car. So that the car tiers exert force on the ground.

The maximum centrifugal force on the car without sliding,

                                          F = mv²/r

                                          v² = Fr/m

                                           v = √(Fr/m)

Substituting the given values

                                           v = √(14700 x 50 / 1500)

                                              = 22.14 m/s

Hence, the maximum velocity of the curve without sliding is, v = 22.14 m/s

a. are

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards