Starting from rest, a 4.10-kg block slides 2.10 m down a rough 30.0° incline. the coefficient of kinetic friction between the block and the incline is (a) determine the work done by the force of gravity. j(b) determine the work done by the friction force between block and incline. j(c) determine the work done by the normal force. j(d) qualitatively, how would the answers change if a shorter ramp at a steeper angle were used to span the same vertical height

Answer

mass of the block = 4.10 Kg

distance of slide = 2.1 m

angle of inclination = 30.0°

μ_k be equal to 0.436

a) Work done by the gravity

b) Work done due to friction =

                              =  

                              =  

                              = -31.86 J

c) work done by the normal force = 0 J

Since normal force and displacement are perpendicular to each other

d) for steeper angle

   sin θ value is high

   cos θ value is less

   work done by gravity on steeper angle is more

   work done by frictional force will on steeper angle is less

   work done by normal force is zero

answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

read more on -