Two bicycle tires are set rolling with the same initial speed of 3.90 m/s along a long, straight road, and the distance each travels before its speed is reduced by half is measured. one tire is inflated to a pressure of 40 psi and goes a distance of 18.6 m ; the other is at 105 psi and goes a distance of 93.1 m . assume that the net horizontal force is due to rolling friction only and take the free-fall acceleration to be g = 9.80 m/s2 . what is the coefficient of rolling friction (uk) for the tire under low pressure?

0.03129

Explanation:

= Coefficient of rolling friction

g = Acceleration due to gravity = 9.8 m/s²

Initial speed of both the bicycles is

u = 3.9 m/s

Final velocity

a = Acceleration =

Equation of motion

The coefficient of rolling friction for the tire under low pressure is 0.03129

electric field is a function of 1/r^2

yes, the force per unit charge for a point charge is inverse square law.

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j