Consider two particles a and b. the angular position of particle a, with constant angular acceleration, depends on time according to =θ₀+ω₀t+12αt² . at time t=t₁, particle b, which also undergoes constant angular acceleration, has twice the angular acceleration, half the angular velocity, and the same angular position that particle a had at time t=0.how long after the time t₁ does the angular velocity of b have to be to equal a's?

Explanation:

After time "t" the angular position of A is given as

now we know that B start motion after time t1

so its angular position is also same as that of position of A after same time "t"

so we have

now since both positions are same

i think the answer is a, hope this is right, that would be my best guess.

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hope this !