Two toroidal solenoids are wound around the same form so that the magnetic field of one passes through the turns of the other. solenoid 1 has 690 turns and solenoid 2 has 450 turns. when the current in solenoid 1 is 6.60 a, the average flux through each turn of solenoid 2 is 3.50×10-2 wb.

a: what is the mutual inductance of the pair of solenoids?

b: when the current in solenoid 2 is 2.60 a, what is the average flux through each turn of solenoid 1?

The concept that we need here to give a proper solution is mutual inductance.

The mutual inductance  is given by the expression

Where,

I = current

N = Number of turns

Flux through the solenoid.

Part A) Then we have in our values that,

Replacing in the equation,

Part B) Here is required the Flux, then using the same expression we have that

We conserve the same value for the Inductance but now we have a current of 2.6, then

Therefore the flux in Solenoid 1 is

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