You and your brother are pushing a car with dead battery with forces of 20n and 25 n in the same direction what is the net force applied on the car

The net force, F = 45 N

Explanation:

Given,

I applied a force on the car, F₁ = 20 N

My brother applied a  force on the car, F₂ = 25 N

Neglecting the frictional force of the car

The two forces act in the same direction, so the magnitude of the resultant force is equal to the algebraic sum of the individual forces. The direction of the resultant force is along the line of the original force.

The net force is given by the formula,

                                          F = F₁ + F₂

Substituting the given values in the above equation,

                                          F = 20 N + 25 N

                                             = 45 N

Hence, the resultant force applied to the car is, F = 45 N

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

a. are