Achild slides down a slide with a 28° incline, and at the bottom her speed is precisely one half what it would have been if the slide had been frictionless. calculate the coefficient of kinetic friction between the slide and the child. here's the two equations i used: sin28*m*g=m(v2/t) since v2=v1+at the other one is with friction: sin28*m*g-u*cos28*m*g=m((1/2*v2)/t)

μ=0.13

Explanation:

If there would be no friction:

Solving for the speed:

Since her speed is precisely one half what it would have been if the slide had been frictionless:

By kinetics equation:

  where Vo=0

Solving for a:

By a sum of forces:

 where

Replacing the value for N, and a:

Solving for μ:

overcharge is the right answer system

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards