Agymnast of mass 69.0 kg hangs from a vertical rope attached to the ceiling. you can ignore the weight of the rope and assume that the rope does not stretch. use the value 9.81 m/s2 for the acceleration of gravity. calculate in newtons: a) the tension t in the rope if the gymnast hangs motionless on the rope. b) the tension t in the rope if the gymnast climbs the rope at a constant rate. c) the tension t in the rope if the gymnast climbs up the rope with an upward acceleration of magnitude 0.700 m/s2.d) the tension t in the rope if the gymnast slides down the rope with a downward acceleration of magnitude 0.700 m/s2.

Part a)

Part b)

Part c)

Part d)

Explanation:

Part a)

Since the gymnast is holding the rope and remains stationary

So total force is balanced on it

so we will have

T = mg

Part b)

Now gymnast start climbing the rope at uniform speed

so here we have

so again we will have same force equation

Part c)

Now gymnast start climbing up the rope at uniform acceleration

so now we will have

Part d)

Now gymnast start sliding downwards with same uniform acceleration

so now we will have

now we have

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explanation: