Aviscous fluid is flowing through two horizontal pipes. the pressure difference p1 - p2 between the ends of each pipe is the same. the pipes have the same radius, although one is twice as long as the other. how does the volume flow rate qb in the longer pipe compare with that in the shorter pipe?

half of shorter Pipe

Explanation:

Fluid is Flowing through two horizontal pipes with pressure difference

Both pipes have same radius

Length of one Pipe is twice of other

Let Longer Pipe be denote by 1 and smaller by 2

From Hagen Poiseuille equation

Where viscosity of medium

L=length of Pipe

Q=discharge

D=diameter

For longer Pipe

----1

For smaller Pipe

------2

From  1 &  2 we get

volume flow rate of longer pipe is half of smaller pipe

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//