Birdman is flying horizontally at a

speed of 21 m/s and a height of 97

m. birdman releases a turd directly

above the start of the field how far

from the start of the field should the

robot hold the bucket to catch the

turd?

X=92.49 m

Explanation:

Given that

u= 21 m/s

h= 97 m

Time taken to cover vertical distance h

h= 1/2 g t²

By putting the values

97 = 1/2 x 10 x  t²          ( g = 10 m/s²)

t= 4.4 s

The horizontal distance

X= u .t

X= 21 x 4.4

X=92.49 m

the components of a vector are the parts of the vectors that are to each other.

b perpendicular

can u provide the graph and if its not possible

then i can tell u the segment where the

average time interval starts degrading is the segment where the car is slowing down