A10 kg block is pushed with a constant horizontal force of 20 n against a constant horizontal frictional force of 10 n. what is the acceleration of the block?

The acceleration would be a=1 m/s^2. Let's explain why.

Explanation:

Let's say the block is □

20N→□    Block is pushed with a constant horizontal force of 20N

□←10N     It is known that frictional force is the opposite way of the movement

So it is safe to say that there is 10 N force trying to stop the block.

In this case our net force is

According to Newton's second motion law

(m=mass, F=force, a=acceleration

→

As an extra information the block also applies gravitational m.g force down but since there is no other force applies in the vertical way, ground compansate the force.

the answer for apex is the lowest

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day