An air capacitor is made from two flat parallel plates 1.50 mm apart. the magnitude of charge on each plate is 0.0180 μc when the potential difference is 200 v.

The capacitance is 90 pF.

Explanation:

Given that,

Distance between the plates= 1.50 mm

Charge on each plate = 0.0180μC

Potential difference = 200 V

Suppose we find the capacitance

We need to calculate the capacitance

Using formula of capacitance

Where, Q = charge

C = capacitance

V = potential

Put the value into the formula

Hence, The capacitance is 90 pF.