A0.366 kg metal cylinder is placed inside the top of a plastic tube, the lower end of which is sealed off by an adjustable plunger, and comes to rest some distance above the plunger. the plastic tube has an inner radius of 7.24 mm, and is frictionless. neither the plunger nor the metal cylinder allow any air to flow around them. if the plunger is suddenly pushed upwards, increasing the pressure between the plunger and the metal cylinder by a factor of 1.59, what is the initial acceleration of the metal cylinder? assume the pressure outside of the tube is 1.00 atm.

Explanation:

As we know that pressure between the cylinder and plunger is increased by 1.59 times

So this will make a net force upwards on the cylinder which is given as

now we will have

Here initial pressure is given as

now new pressure is given as

so we have force on the cylinder given as

now the acceleration is given as

hotter stars = bluer stars

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂