Find the equivalent resistance, the current supplied by the battery and the current through each resistor when the specified resistors are connected across a 2-v battery. part (a) uses two resistors with resistance values that can be set with the animation sliders, and you can use the animation to verify your calculation. in part (b), three resistors are specified.

(a) two resistors are connected in series across a 2-v battery. let r1 = 10 ? and r2 = 9 ? .
req = ?
i = a
? v1 = v
? v2 = v

= 19  Ω,   I = 0.105 A,   V1 = 1.05 V  and    V2 = 0.95 V

Explanation:

The correct way to solve this type of problem is to find the current or voltage values for the equivalent resistance and from here find the other values.

For a series circuit the equivalent resistance is the sum of the resistance

      = R1 + R2

        = 10 +9

        = 19  Ω

Let's use the equation for the voltage

     V = I

      I = V /  

      I = 2/19

      I = 0.105 A

In a series circuit the current is constant, so let's use the voltage equation for each resistor

     V1 = I R1

     V1 = 0.105 10

     V1 = 1.05 V

     V2 = 0.105 9

     V2 = 0.95 V

Note that the sum of this voltage is the total voltage applied.

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.