A0.40-kg object is traveling to the right (in the positive direction) with a speed of 4.0 m/s. after a 0.20 s collision, the object is traveling to the left at 3.0 m/s. what is the magnitude of the impulse (in n-s) acting on the object? the answer must be positive. (never include units in the answer to a numerical question.)

Explanation:

It is given that,

Mass of the object, m = 0.4 kg

Speed of the object, u = 4 m/s

After the collision, the object is travelling, v = -3 m/s (to left)

Time, t = 0.2 seconds

Let J is the impulse acting on the object. We know that the impulse of an object is equal to the change in momentum. It can be calculated as :

J = -2.8 kg-m/s

|J| = 2.8 kg-m/s

So, the impulse acting on the object has a magnitude of 2.8 kg-m/s. Hence, this is the required solution.

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!

that tool is called an altimeter which measures your altitude which can be used to tell which atmosphere you are currently in, including the stratosphere.

hope this ! : )