subject
Physics, 31.10.2019 06:31 AaronEarlMerringer

You stand new the earth's equator. a positively charged particle that starts moving parallel to the surface of the earth in a straight line directed cast is initially deflected upwards. if you know there are no electric fields in the vicinity, a possible reason why the particle does not initially acquire a downward component of velocity is because near the equator the magnetic field lines of the earth are directed
a. upward.
b. downward.
c. from south to north.
d. from north to south.
e. from east to west.

ansver
Answers: 1

Other questions on the subject: Physics

image
Physics, 22.06.2019 01:10, joejoefofana
Suppose that two tanks, 1 and 2, each with a large opening at the top, contain different liquids. a small hole is made in the side of each tank at the same depth 1.57 m below the liquid surface, but the hole in tank 2 has 2.49 times the cross-sectional area of the hole in tank 1. (a) what is the ratio ρ1/ρ2 of the densities of the liquids if the mass flow rate is the same for the two holes? (b) what is the ratio rv1/rv2 of the volume flow rates from the two tanks? (c) at one instant, the liquid in tank 1 is 14.9 cm above the hole. if the tanks are to have equal volume flow rates, what height above the hole must the liquid in tank 2 be just then?
Answers: 3
image
Physics, 22.06.2019 16:30, sti192
The air in an automobile tire with a volume of 2.60 ft3 is at 70°f and 21 psig. determine the amount of air that must be added to raise the pressure to the recommended value of 30 psig. assume the atmospheric pressure to be 14.6 psia and the temperature and the volume to remain constant. the gas constant of air is ru = 53.34ft⋅lbflbm⋅r(1 psia144 lbf/ft2) = 0.3704 psia⋅ft3lbm⋅r the amount of air that must be added to raise the pressure is lbm
Answers: 3
image
Physics, 22.06.2019 17:30, BabyG1353
Asilver dollar is dropped from the top of a building that is 1324 feet tall. use the position function below for free-falling objects. s(t) = −16t2 + v0t + s0 (a) determine the position and velocity functions for the coin. s(t) = v(t) = (b) determine the average velocity on the interval [1, 2]. ft/s (c) find the instantaneous velocities when t = 1 second and t = 2 seconds. v(1) = ft/s v(2) = ft/s (d) find the time required for the coin to reach the ground level. (round your answer to three decimal places.) t = s (e) find the velocity of the coin at impact. (round your answer to three decimal places.) ft/s
Answers: 3
image
Physics, 22.06.2019 17:40, 573589
You throw a baseball directly upward at time =0 at an initial speed of 14.9 m/s. what is the maximum height the ball reaches above where it leaves your hand? ignore air resistance and take =9.80 m/s2.
Answers: 1
You know the right answer?
You stand new the earth's equator. a positively charged particle that starts moving parallel to the...

Questions in other subjects:

Konu
Mathematics, 02.03.2021 04:40
Konu
History, 02.03.2021 04:40