Based on the data collected, explain why a launch angle of 30 degrees (high horizontal velocity & small time of flight) will allow a projectile to go just as far when the launch angle of 60 degrees (low horizontal velocity and large time of flight).

Explanation:

The horizontal distance traveled by the projectile is given by the formula

The formula for the time of flight is given by

Case I: when the launch angle is 30°

So,

Horizontal velocity = u Cos 30 = 0.866 u

Case II: when the launch angle is 60°

Horizontal velocity = u Cos 60 = 0.5 u

By observing the case I and case II, we conclude that

R1 = R2

Horizontal velocity 1 > Horizontal velocity 2

T1 < T2

d) physical means can be used to separate the components of air.

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach