Blocks with masses of 1.0 kg, 2.0 kg, and 3.0 kg are lined up in a row on a frictionless table. all three are pushed forward by a 17 n force applied to the 1.0 kg block.

part a:
how much force does the 2.0 kg block exert on the 3.0 kg block?

part b
how much force does the 2.0 kg block exert on the 1.0 kg block?

The 2.0 kg block exert 8.5 Newton on the 3.0 kg block

The 2.0 kg block exert 14¹/₆ Newton on the 1.0 kg block

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

We will use Newton's 2nd law formula for this problem.

The force acting on the 3.0 kg block could be calculated as follows:

The force acting on the 1.0 kg block could be calculated as follows:

Grade: High School

Subject: Physics

Chapter: Dynamics

Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.