You are driving through town at 12.0 m/s when suddenly a ball rolls out in front of you. you apply the brakes and begin slowing at a rate of 3.5 m/s2. how far did you travel before stopping? what variable represents 3.5 m/s2?

20.6 m, acceleration

Explanation:

Since this is a uniformly accelerated motion, we can solve the problem with the following suvat equation:

where

v = 0 is the final velocity of the driver (since he comes to a stop)

u = 12.0 m/s is the initial velocity

is the acceleration, which is negative since the car is slowing down (so its direction is opposite to the motion)

s is the distance covered by the car while stopping

Solving the equation for s, we find the distance covered:

And as we said previously, is the magnitude of the acceleration, which represents the rate of change of the velocity.

0.11 m/s and 0.28 m/s should be correct

f=ma newton

f=100x2.5=250n