(1) how much work is required to stop an electron
(m = 9.11 x 10-31 kg) which is moving with a speed
of 1.90 x 10 m/s?

Explanation:

We can solve the problem by using the work-energy theorem: in fact, the work done on the electron must be equal to its change in kinetic energy, therefore

where

is the mass of the electron

v = 0 is the final velocity of the electron (it comes to a stop)

u is the initial velocity of the electron

In the problem, we are told that the electron is initially moving at

Therefore, the work required to stop is is

and the work is negative since it is in the opposite direction to the motion of the electron.

pe = weightxheight = 2000x1000=2,000,000joules

this is an example of "committed" time.

committed time, as contracted time, takes need over essential and available time since it is seen as profitable work. it alludes to the time allotted to keep up a home and family. at the point when a man is commuting using committed time this individual may feel that the drive is an obligation to family, for example, strolling youngsters to class or driving a mate to work. contracted and committed time clients may feel that their commute could really compare to the commute of important or leisure time clients on the grounds that their commute is profitable work. in this manner, they might be more disposed to pick a mechanized method of movement.