Physics, 29.10.2019 07:31 meaghangreenwa

A1000-kg car is moving at 30 m/s around a horizontal unbanked curve whose diameter is 0.20 km. what is the magnitude of the friction force required to keep the car from sliding?

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Answer from: user1234536

Explanation:

It is known that relation between force, mass, velocity and radius is as follows.

F = $\frac{mv^{2}}{r}$

As diameter is given as 0.20 km. So, radius is $\frac{diameter}{2}$ . Hence, radius will be equal to 0.10 km.

As, 1 km = 1000 m. Therefore, 0.10 km = 100 m.

Also, it is given that mass is 1000 kg and velocity is 30 m/s. Hence, calculate the force required to keep the car from sliding will be as follows.

F = $\frac{mv^{2}}{r}$

= $\frac{1000 kg \times (30)^{2}}{100 m}$

= 9000 N

Thus, we can conclude that the magnitude of the friction force required to keep the car from sliding is 9000 N.

Answer from: yahnna8

The frictional force required to keep the car from sliding is 9,000 N.

The given parameters;

mass of the car, m = 1000 kg

velocity of the car, u = 30 m/s

diameter of the curve, d = 0.2 km = 200 m

radius of the curve, r = 100 m

The frictional force required to keep the car from sliding is the centripetal force keeping the car moving without sliding.

The frictional force required to keep the car from sliding is calculated as follows;

$F_c = \frac{mv^2}{r} \\\\F_c = \frac{1000 \times 30^2 }{100} \\\\F_c = 9,000 \ N$

Thus, the frictional force required to keep the car from sliding is 9,000 N.

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A1000-kg car is moving at 30 m/s around a horizontal unbanked curve whose diameter is 0.20 km. what...