What is an object's final velocity if it has an initial velocity of +12
meters/second with a constant acceleration of +14
meters/second and has traveled 48 meters in the +x direction?

v = 38.57 m/s

Explanation:

Given that,

The initial velocity of the object in x direction, u = 12 m/s

The acceleration of the object in x direction, a = 14 m/s²

The distance traveled by the object in x direction, s = 48 m

The equations of motion of a moving body with initial velocity and acceleration is given by the formula

                                      v² = u² + 2as

Substituting the values in the above equation

                                      v² = (12 m/s)² + 2 x 14 m/s² x 48 m

                                           = 1488

Therefore,                      

                                        v = 38.57 m/s

Hence, the final velocity of the body, v = 38.57 m/s