Two students are on a balcony 18.5 m above the street. one student throws a ball ver- tically downward at 13.8 m/s; at the same instant, the other student throws a ball verti- cally upward at the same speed. the second ball just misses the balcony on the way down. how far apart are the balls 0.361 s after they are thrown? the acceleration of gravity is 9.8 m/s2 .

11.24m

Explanation:

Given that:

Using the equations of motion:

To find the final velocity after the given time 0.361 second.

................ (1)

where:

Putting the values of the respective balls

Similarly  

 ∵the body is thrown against the gravity will have decelerating effect.

∵the body is still moving up with this velocity

Now, using the eq.

.............................(2)

where, the symbols have usual meaning as above and:

Putting the respective values in eq. (2)

For the body in the first case:

For the body in the second case:

∴The bodies are apart from each other from the point from which they are thrown.

c. 7/3

step-by-step explanation:

a rational number is like pi- it is a repeating decimal.

a. is -1.8

b. 2.236068

c. 2.3333333333333333333

d.   is 3

i hope that ! =)

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2