Askater goes down a hill with a constant acceleration of 2.25 m/s2 for 50 meters. if the skater's final velocity was 20 m/s, calculate her initial velocity.

The initial velocity of the skater is 13.22 m/s.

Explanation:

Given that,

Acceleration of the skater,

Distance covered, d = 50 m

The skater's final velocity was, v = 20 m/s

We need to find the initial velocity of the skater. It can be calculated using third equation of motion as :

So, the initial velocity of the skater is 13.22 m/s. Hence, this is the required solution.

Learn more,

Kinematics

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards