Ablock of mass m = 0.600 kg is pressed against a horizontal spring of elastic constant k = 20 n/m, compressing it by 20.0 cm. the block is then released. once it loses contact with the spring, the block travels a distance 33 cm on a rough horizontal surface before it comes to a stop. what is the coefficient of kinetic friction between the block and the surface?

The coefficient of kinetic friction is 1.03

Explanation:

Step 1: Given data

⇒ mass of the block = 0.600 kg

⇒ elastic constant k = 20 N/m

⇒ The spring is compressed by 20.0 cm (=x) = 0.2 m

⇒ Once it loses contact with the spring, the block travels a distance 33 cm

Step 2: Calculate the potential energy

Ep = 1/2 * k * x²

Ep = 1/2 * 20N/m * (0.2m)²

Ep = 0.4 Nm

Step 3: Calculate the coefficient of kinetic friction

At the end of the movement Potential energy = work

W = Ep = 0.4Nm =  µx * m * g* x

µx = Ep / (m*g*x)

µx = 2Nm / ( 0.6 kg * 9.81 m/s² * 0.33m)

µx = 1.03

The coefficient of kinetic friction is 1.03

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min