Aprofessional golfer is examining a video of a practice swing. the high‑speed footage shows that his club is in contact with the ball (which was initially at rest on the tee) for only δ=0.371 ms, and the radar gun clocks the speed of the ball as =146 mph after it comes off the club. the golf ball has a mass of mb=45.9 g. what is the magnitude of the impulse imparted to the ball by the club? magnitude of the impulse: kg⋅ms what is the magnitude of the average force of contact between the club and the ball? magnitude of the average force of contact:

Explanation:

The impulse imparted can be obtained using the equation . In our case, since the ball departs from rest, we have:

We can convert this to S.I. using the corresponding conversion factors (which are equal to 1, thus not altering our value):

Since also the impulse relates to the average force by the equation , we can use our values to calculate this force:

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.