You have been called to testify as an expert witness in a trial involving a head-on collision. car a weighs 680.0 kg and was traveling eastward. car b weighs 510.0 kg and was traveling westward at 72.0 km/h. the cars locked bumpers and slid eastward with their wheels locked for 6.00 m before stopping. you have measured the coefficient of kinetic friction between the tires and the pavement to be 0.750. 1) how fast (in kilometer per hour) was car a traveling just before the collision? (express your answer to three significant figures.

Explanation:

In order to know the velocity of the cars after the collision, we must calculate the acceleration after the collision. According to Newton's second law:

Using the following kinematics equation, we calculate the initial velocity which is the same velocity after collision, so, the final velocity is zero since the cars stopped after 6 meters:

According to the law of conservation of momentum and solving for :

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.