Aloudspeaker of mass 20.0 kg is suspended a distance of h = 2.20 m below the ceiling by two cables that make equal angles with the ceiling. each cable has a length of l = 2.90 m . what is the tension t in each of the cables?
use 9.80 m/s2 for the magnitude of the acceleration due to gravity.

The tension T in each of the cables, T = 98 N

Explanation:

Given,

The mass of the loudspeaker, m = 20.0 Kg

The suspended distance of the loudspeaker, d = 2.20 m

The length of each cable, l = 2.9 m

The tension experienced by the cable is given by the formula,

                           T = mg + ma    newton

Where,

                        g - acceleration due to gravity

                        a-acceleration produced by the stretched cable

Since the stretched cable and loudspeaker is not moving, then the tension force acting on the cable is equal to the force of gravity.

                              T = mg  newton

Substituting the values in the above equation

                              T = 20

                                 = 20.0 Kg x 9.8 m/s²

                                 = 196 N

This force is equally supported by the two cables, then the tension in each cable is

                                  T = 196 N / 2

                                     = 98 N

Hence, the tension T in each of the cables, T = 98 N

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.