You have two resistors with the same cross sectional area and resistivity. resistor a has length l1 and resistor b has length l2. assume l2 > l1. if the resistors are connected in series with a battery, which resistor has the most power delivered to it? explain. b: if they are connected in parallel with a battery, which resistor has the most power delivered to it? explain.

Explanation:

Given

Resistor A has length

and Resistor B has Length

and Resistance is given by

Considering and A to be constant thus

because

(a)When they are connected in series

As the current in series is same and power is

therefore as R is greater for second resistor

(b)if they are connected in Parallel

In Parallel connection Voltage is same

resistance of 2 is greater than 1 thus Power delivered by 1 is greater than 2

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.