An asteroid of mass 5.7×104 kg carrying a negative charge of 14.0 μc is 190 m from a second asteroid of mass 5.5×104 kg carrying a negative charge of 15.0 μc. what is the net force the asteroids exert upon each other? (g = 6.673 x 10-11 n∙m2/kg2 and k = 9.0 x 109 n∙m2/c2.) an asteroid of mass 5.7×104 kg carrying a negative charge of 14.0 μc is 190 m from a second asteroid of mass 5.5×104 kg carrying a negative charge of 15.0 μc. what is the net force the asteroids exert upon each other? (g = 6.673 x 10-11 n∙m2/kg2 and k = 9.0 x 109 n∙m2/c2.) 5.6×105 n 5.4×105 n 5.7×10−3 n 4.7×10−5 n

repulsion force es  R = 5,224 10⁻³ N

Explanation:

We use Newton's second law to add forces, the elective force is repulsive because the asteroids have the same type of charge and gravitational force is always attractive.

Gravitational force

      Fg = G m1 m2 / r²

      Fg = 6,673 10⁻¹¹ 5.7 10⁴ 5.5 10⁴/190²

      Fg = 5,795 10⁻⁶ N

Electric force

     Fe = k q1 q2 / r²

     Fe = 8.99 10⁹ 14.0 10⁻⁶ 15.0 10⁻⁶ / 190²

     Fe = 5.2296 10⁻³ N

The resulting force is

     R = Fe - Fg

     R = 5.2296 10⁻³ - 5.795 10⁻⁶=  5229.6 10⁻⁶ - 5,795 10⁻⁶

     R = 5,224 10⁻³ N

this is a repulsive force and the asteroids move away from each other

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

c) power lifting, will be your answer.

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deku ❤