Iwatched an astronaut drop a feather one the moon. it took 1.3 seconds. how fast was it going right before it hit the lunar surface if freefall acceleration on the moon is 1.62 m/s^2?

The final velocity of feather, v = 2.106 m/s

Explanation:

Given that,

The initial velocity of the feather, u = 0 m/s

Freefall acceleration of the moon, a = 1.62 m/s²

Time taken by the feather to reach the lunar surface is, t = 1.3 s

The final velocity of the feather, v = ?

The equation of motion is given by the relation

                                    v = u + at

Substituting the values in the above equation

                                    v = 0 + 1.3 s · 1.62 m/s²

                                       = 2.106 m/s

Hence, the speed of the feather right before it hit the lunar surface is, v = 2.106 m/s

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards