Acrate is pushed horizontally by a horizontal force 527.018 n . sliding friction resists the motion, and the kinetic coefficient of friction is 0.17 . the acceleration of gravity is 9.8 m/s 2 . calculate the acceleration of the crate. answer in units of m/s 2 .

m= 10 kg a = 52 m / s²

Explanation:

For this problem we must use Newton's second law, let's apply it to each axis

X axis

      F - fr = ma

The equation for the force of friction is

    -fr = miu N

Axis y

     N- W = 0

     N = mg

Let's replace and calculate laceration

     F - miu (mg) = ma

    a = F / m - mi g

    a = 527.018 / m - 0.17 9.8

We must know the mass of the body suppose m = 10 kg

    a = 527.018 / 10 - 1,666

    a = 52 m / s²

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever

the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.