Physics, 22.10.2019 23:00 netflixacc0107

Applying a constant net force to an object causes it to accelerate at 10 m/s2. what will the acceleration of the object be if (a) the force is doubled, (b) the mass is halved, (c) the force is doubled and the mass is doubled, (d) the force is doubled and the mass is halved, (e) the force is halved, (f) the mass is doubled, (g) the force is halved and the mass is halved, and (h) the force is halved and the mass is doubled?

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Answer from: pinkpearl2022

Explanation:

F=ma

The force is directly proportional to mass and acceleration.

a) If force is doubled then acceleration is doubled.

b) If mass is halved then acceleration of the will increase if the force is constant.

c) If the force is doubled and the mass is doubled then acceleration is halved.

$F_1=m_1a_1\\\Rightarrow a_1=\frac{F_1}{m_1}$

$2F_1=2(2m_1)a_2\\\Rightarrow F_1=2m_1a_2\\\Rightarrow a_2=\frac{F_1}{2m_1}$

Dividing the equation

$\frac{a_1}{a_2}=\frac{\frac{F_1}{m_1}}{\frac{F_1}{2m_1}}\\\Rightarrow a_2=\frac{1}{2}a_1$

d) If the force is doubled and the mass is halved then acceleration is doubled

$F_1=m_1a_1\\\Rightarrow a_1=\frac{F_1}{m_1}$

$2F_1=2(\frac{m_1}{2})a_2\\\Rightarrow a_2=2\frac{F_1}{m_)}\\\Rightarrow a_2=\frac{F_1}{2m_1}$

e) If the force is halved then the acceleration is halved.

f) If the mass is doubled then the acceleration is halved keeping the constant force

g) If the force is halved and the mass is halved then the acceleration is doubled

$F_1=m_1a_1\\\Rightarrow a_1=\frac{F_1}{m_1}$

$\frac{1}{2}F_1=\frac{1}{2}(\frac{m_1}{2})a_2\\\Rightarrow a_2=2\frac{F_1}{m_1}$

h) If the force is halved and the mass is doubled then the acceleration is halved.

$F_1=m_1a_1\\\Rightarrow a_1=\frac{F_1}{m_1}$

$\frac{1}{2}F_1=\frac{1}{2}(2m_1)a_2\\\Rightarrow a_2=\frac{F_1}{2m_1}$

Answer from: Quest

26.4 is about the right time

Answer from: Quest

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.