[high dive) above a pool of water. according to the announcer, the divers enter the water at a speed of 56 mi/h (25 m/s). (air resistance may be ignored in this problem.) ve] visitors at an amusement park watch divers step off a platform 70 ft (a) is the announcer correct in this claim? explain. (b) is it possible for a diver to leap directly upward off the board so that, missing the platform on the way down, the diver enters the water at 25 m/s? if so, what initial upward speed is required? is the required initial speed physically attainable? how do you know?

(a) The announcer's claim is incorrect because the divers enter at a speed of 20.4 and not 25 m/s as announced

(b)  it’s possible for a diver to enter the water with the velocity of 25 m/s if he has initial velocity of 14.4 m/s. The upward initial velocity can’t be physically attained

Explanation:

(a)

To find the final velocity for an object traveling distance h taking the initial vertical component of velocity as the kinematics equation is written as

where a is acceleration

Substituting g for a where g is gravitational force value taken as 9.81

Since the initial velocity is zero, we can solve for final velocity by substituting figures, note that 70 ft is 21.3 m for h

= 20.44275

Therefore, the divers enter with a speed of 20.4 m/s

The announcer's claim is incorrect because the divers enter at a speed of 20.4 and not 25 m/s as announced

(b)

The divers can enter water with a velocity of 25 m/s only if they have some initial velocity. Using the kinematic equation

Since we have final velocity of 25 m/s

= 14.390761 m/s

Therefore, it’s possible for a diver to enter the water with the velocity of 25 m/5 if he has initial velocity of 14.4 m/s

In conclusion, the upward initial velocity can’t be physically attained

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