Atruck is using a hook to tow a car whose mass is one quarter that of the truck. if the force exerted by the truck on the car is 6000 n, then the force exerted by the car on the truck is 1500 n 24000 n 6000 n 12000

This question can be solved using the concept of Newton's Third Law of Motion and force.

The force exerted by the car on the truck is "6000 N".

Newton's Third Law of Motion states that "to every action force there is an equal but opposite reaction force". It means that whenever an object applies a force on another object, the second object will also apply a reaction force on the first object. This reaction force will always have the same magnitude as the applied force, but the opposite direction as compared to the applied force.

Hence, the magnitude of the reaction force applied by the car on the truck will be equal to the magnitude of the force applied by the truck on the car.

Force exerted by the car on the truck = F = Force exerted by the truck on the car

F = 6000 N

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The attached picture shows the Newton's Third Law of Motion.

6000 N

Explanation:

Newton's third law states that:

"When an object A exerts a force (called action) on an object B, then object B exerts an equal and opposite force (called reaction) on object A"

In this problem, we can identify:

- The truck as object A

- The car as object B

This means that if the force exerted by the truck on the car (the action) is 6000 N, then the force exerted by the car on the truck (the reaction) must also have equal magnitude, 6000 N, and be in the opposite direction.

answer would be d.) i hope this

explanation:

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