A60-kg box is being pushed a distance of 7.9 m across the floor by a force upper poverscript right-arrow endscripts ⁢ whose magnitude is 194 n. the force upper poverscript right-arrow endscripts ⁢ is parallel to the displacement of the box. the coefficient of kinetic friction is 0.23. determine the work done on the box by each of the four forces that act on the box. be sure to include the proper plus or minus sign for the work done by each force.

Explanation:

Given

mass of box=60 kg

distance=7.9 m

Force is parallel to displacement

coefficient of kinetic energy

Work done by Force

Work done by Friction force

negative sign indicates that force is opposite to displacement

Work due to Weight and Normal reaction is zero as the force is perpendicular to Displacement

work: w = fd (given)

work done by chet   =50*1 = 50 j

work done by mika =40*2 = 80 j

work done by sara =30*1.5 = 45 j

work done by bill =60*0.5 = 30 j

students in order from the greatest amount of work done to the least is mika> chet> sara> bill

hence option (b) is correct.

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer