Aparachutist weighs 1000n. when she opens her parachute, it pulls upwards on her with a force of 2000n. (a) draw a diagram to show forces acting on the parachutist. (b) calculate the resultant forces acting on the parachutist. (c) what effect will this force have on her ?

Explanation:

a) diagram is shown in attached figure.

b)

                        Resultant Force= Fnet= 2000-1000= 1000 N   (upward)

c)the force will lift parachutist  upward with acceleration  =Fnet/ m

where m is mass of parachutist    

                                                      m=weight/g

                                                          =1000/10=100 kg

               acceleration of parachutist=Fnet/ m

                                                            =1000/100

                                                      a=10 m/s²

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards