Physics, 18.10.2019 17:20 mcsaggers2842

In a laboratory test of tolerance for high acceleration, a pilot is swung in a circle 13.0 m in diameter. it is found that the pilot blacks out when he is spun at 30.6 rpm (rev/min).

a) at what acceleration (in si units) does the pilot black out?

b)if you want to decrease the acceleration by 12.0% without changing the diameter of the circle, by what percent must you change the time for the pilot to make one circle?

Answers: 2

Show answers

Answers

Answer from: griffinadrianne946

a) a = 10,270 m/s² and b) 34%

Explanation:

Let's start by reducing the units to the SI system

w = 13 rpm (2pirad / 1rev) 1 min / 60s) = 1,257 rad / s

R = D / 2 = 13.0 / 2 = 6.50 m

a) The formula for centripetal acceleration is

a = w² R

a = 1,257 2 6.50

a = 10,270 m / s²

b) Let's calculate how much 12% of the acceleration is and subtract them

12% a = 10.270 12/100 = 1.2324

The new acceleration is

a2 = a - 12% a

a2 = 10.270 -1.2324

a2 = 9.0376 m / s²

Let's calculate the time of a revolution, which we will call period for the two accelerations.

a = v² / r

a = (2 π R / T)² / R = 4 π² R / T²

T = √4 π² R/a

T= 2π √(R/a)

First acceleration

T1 = 2 π √6.50/10.270

T1 = 4.999s

Acceleration reduced 12%

T2 = 2 π √6.5/9.0376

T2 = 6.721 s

Period change

ΔT = T2-T1 =4.999 - 6.721 = -1.72 s

Let's calculate the change from the initial period

% = Δt / T1 100

% = 1.72 / 4.999 100

% = 34%

The period must be reduce by this amount

Answer from: wsdafvbhjkl

We have that for the Question "a) At what acceleration (in SI units) does the pilot black out?

b)If you want to decrease the acceleration by 12.0% without changing the diameter of the circle, by what percent must you change the time for the pilot to make one circle?"

It can be said that

The acceleration the pilot blacks out = 56.419m/s^2

Percent change for the pilot to make one circle = $13.2\%\\$

From the question we are told

a pilot is swung in a circle 13.0 m in diameter. It is found that the pilot blacks out when he is spun at 30.6 rpm (rev/min).

Converting the angular velocity to rad/sec

$w = \frac{30.6*2\pi}{60}\\\\= 3.2028rad/sec$

Acceleration,

$a = w^2R\\\\= w^2*\frac{D}{2}\\\\=w^2*\frac{11}{2}\\\\=3.2028^2*5.5\\\\=56.419m/s^2$

Time period, T

$T = \frac{2\pi}{w}\\\\= 2\pi*\sqrt\frac{R}{a}$

acceleration decreased by 22%

$T^1 = 2\pi*\sqrt\frac{R}{0.78a}\\\\T^1 = 2\pi*\sqrt\frac{R}{a} * 1.132\\\\T^1 = 1.132T$

Therefore, change in time

$\delta T = \frac{T_0-T_1}{T_1}*100\\\\= \frac{(1.132)T-T}{T}*100\\\\= 13.2\%$

For more information on this visit

link

Answer from: Quest

force required to detach it is given by

$f = 4 * 10^{-8} n$

charges are taken to be fundamental charge

$q_1 = q_2 = 1.6 * 10^{-19}c$

now we have

$f = \frac{kq_1q_2}{r^2}$

$4 * 10^{-8} = \frac{9*10^9 * 1.6*10^{-19}* 1.6* 10^{-19}}{r^2}$

$r = 7.6 * 10^{-11} m$

so above is the minimum distance at which it will detach

Answer from: Quest

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle

Other questions on the subject: Physics

Physics, 22.06.2019 22:00, 727

Will mark brainliest! asap! ! 16) which of the clouds shown would indicate a possible future rain storm? a) b) c) d)

Answers: 1

continue

Physics, 22.06.2019 22:00, lex1kkkk

The inside surface of a cylindrical-shaped cave of inner diameter 1.0 m is continuously covered with a very thin layer of water. the cave is very long and it is open on both ends. the water on the cave surface is at a constant temperature of 15.5 °c. the cave is constantly exposed to wind such that 15.5 °c air flows through the cave at 4.5 m/s. the kinematic viscosity of the air is 14.66 x 10-6 m2/s and the molecular diffusion coefficient of water vapor in the air is 0.239 x 10-4 m2/s. because the cave diameter is so large, the flow of wind down the length of the cave, in the x direction, can be treated like it is external flow and the cave surface can be approximated as flat where appropriate. calculate the x value, in a) the transition to turbulent flow occurs at rex meters, where the air flow transitions from laminar to turbulent along the inside surface of the cave b) calculate the x value, in meters, where the bulk steady state concentration of water vapor in the air flowing in the cave is 10% of the saturation concentration. assume the air at the surface of the water layer is 100% saturated with water vapor. assume the wind entering the cave contained no moisture before it entered the cave. take into account the transition from laminar to turbulent flow when solving part b

Answers: 1

continue

Physics, 23.06.2019 02:00, hgg44137

Employer informs its employees that it will hold a substantial cash prize drawing for each work group at the end of each month in which no employee in the work group sustains a lost-time injury. tyra reports an injury that she sustained while operating a mechanical power press. tyra did not violate any employer safety rules when she sustained her injury. tyra’s injury requires her to miss work for two days. her employer cancels the cash prize drawing for that month for tyra’s work group because of tyra’s lost-time injury. did the employer misuse an incentive program to retaliate against tyra?

Answers: 3

continue

Physics, 23.06.2019 03:30, prelogical

Blank is the perceived frequency of a sound wave

Answers: 1

continue

You know the right answer?

In a laboratory test of tolerance for high acceleration, a pilot is swung in a circle 13.0 m in diam...