A11kg block slides up a 30° inclined plane at a constant velocity. the coefficient of friction between the block and the plane is μk=0.2. in order for the block to slide up the incline, someone must apply a force to the block. what is the magnitude of the applied force if it points horizontally?

The magnitude of the applied force is 94.74 N

Explanation:

Mass of the block, m = 11 kg

Angle of inclination of the plane,

Friction coefficient,

Now,

Normal force that acts on the block is given by:

          (1)

Now, to maintain the equilibrium parallel to ramp the forces must be balanced.

Thus

                      (2)

From eqn (1) and (2)

F = 94.74 N

d. learned preferences i believe is your answer

answer would be letter choice (a),   a ball resting on a shelf. would be another example of potential energy   >   stored energy > not moving.

a ball spinning on a finger   >   kinetic energy > moving energy

a ball rolling on the ground   >   kinetic energy   > moving energy

a   ball flying through the air   > kinetic energy   >   moving energy

hope that                                         : )