A59.7 kg sled sits on an incline (without moving) and the angle with respect to the horizontal is θ = 24 degrees. the y component of the weight of the sled, wy, is : a) 585.657n;
b) 260.751n;
c) 238.208n;
d) 535.024n;

D)535.024N

Explanation:

Hello! The most important thing to solve this exercise is to make a good free body diagram of the sled on the hill, our coordinate system is aligned with the slope while the direction of the weight force will always go down, then divide the weight vector into components and we found Wy, I attached the drawing!

Wy=mgcos24

Wy=(59.7)(9.81)(cos24)=535.024N

small = small current large mag large current

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.