Afireworks shell is accelerated from rest to a velocity of 50.0 m/s over a distance of 0.240 m. (a) how long (in s) did the acceleration last? s (b) calculate the acceleration in m/s^2). (enter the magnitude.) /s^2

0.0096 seconds

5208.33 m/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

The acceleration of the firework shell was 5208.33 m/s²

The acceleration lasted for 0.0096 seconds

(a) 0.0096 sec

(b)

Explanation:

We have given that firewall shell starts from rest so initial velocity u = 0 m/sec

And final velocity v = 50 m/sec

Distance s = 0.240 m

(A) From first equation pf motion we know that v = u+at

So 50 = 0+at

at = 50

Now from second equation of motion

Using the value of at = 50

(b) As at = 50

So

explanation:

to push or pull an object in a certain direction is known as force. a force in moving an object from one place to another.

force depends on the mass of an object. so, more is the mass of an object more will be the force required to move the object.

thus, we can conclude that the use of force to move an object is push or pull.