Acurrent of 2.35 a flows through a 1.11 mm diameter copper wire that is connected to a capacitor plate. the current is directed toward the plate. find the charge transferred to the plate in 1.10 x 10^-3 s.

charge flowing in the copper wire is

Explanation:

We have given current i = 2.35 A

Time through which charge is charge is transferred

We have to find the charge flowing in this time

We know that charge is given by Q = i×t , here i is current and t is time

So charge =

So charge flowing in the copper wire is

we need to know the time interval during which the force acts. impulse of force = momentum change

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.