When 2.50 g of a certain hydrocarbon was completely combusted in a "bomb (constant-volume) calorimeter" with a heat capacity (excluding water) of 350 j/°c and which contained 2.00 liters of water (density = 1.00 g/ml and specific heat capacity = 4.184 j/°c•g), the resulting temperature change was measured to be 5.52°c. calculate the thermal energy (in kj) released per gram of hydrocarbon combusted. (1) 48.1 kj/g (2) 0.773 kj/g (3) 19.2 kj/g (4) 18.5 kj/g (5) 46.2 kj/g

The thermal energy released per gram is 19.2 kJ/g.

(3)  is correct option.

Explanation:

Given that,

Weight of hydrocarbon = 2.50 g

Heat capacity

We need to calculate the thermal energy released

Using formula of thermal energy

Heat released =heat absorb by calorimeter+heat absorb by water

Put the value into the formula

Now, The thermal energy released per gram

Put the value into the formula

Hence, The thermal energy released per gram is 19.2 kJ/g.

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