Two masses hang below a massless meter stick. mass 1 is located at the 10cm mark with a weight of 15kg, while mass 2 is located at the 60cm mark with a weight of 30kg. at what point in between the two masses must the string be attached in order to balance the system?

43.33 cm mark

Explanation:

Given

mass 1 is located at the 10 cm mark with weight of 15 kg

mass 2 is located at 60 cm mark with weight of 30 kg

string should be attached between them to balance the system

so the distance between the the two masses is 50 cm

For system to be balance torque of both the weight must nullify each other

Let us suppose string is at a distance of x cm from 15 kg mass so 30 kg mass is at a distance of 50-x cm

Balancing torque

so string should be at a mark of 10+33.33=43.33 cm

cell differentiation  is how generic embryonic  cells  become specialized  cells. this occurs  through a process called gene expression. gene expression is the specific combination of genes that are turned on or off (expressed or repressed), and this is what dictates how a  cell  functions.

explanation:

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.