Ahockey player has an acceleration of -3.1 m/s ². how long does it take him to come to a complete stop from a speed of 13 m/s?

A hockey player has an acceleration of -3.1 to complete at a speed of 13 m/s it takes him 4.2 seconds.

Explanation:

Applying the 1 \mathrm{st}  Equation of Motion

v = u + at

where v = Final Velocity

u = Initial Velocity

a = acceleration

t = time

Given-

v = 0 m/s (Complete stop)

u = +13 m/s

a =  -3.1 (negative shows deceleration)

Putting the Values

0 = 13 + (-3.1)t

or, 3.1t = 13

or, t=

or, t = 4.1935 seconds = 4.2 s

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

answer///terminator or twilight zone;